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Grade: 8
a stone of mass 6kg is revolved in a verticle circle of t diameter 6m, such that its speed at a point is minimum at that pointn.if the K.E at the same point is 250J , then minimum P.E a that point is
9 months ago

Answers : (1)

18 Points
1 mole H2O = 18 ml
Therefore , 36 ml H2O = 2 mole
Now 1 mole H2O contains 2 mole H and 1mole O
Therefore 2 mole H2O has 4 mole H and 2 mole O
Oxygen and hydogen both exist as a diatomic molecule. Therefore ,
No of moles of H2 = 2
And no of moles of O2 is = 1
Total volume = 36ml
Volume of H2 and O2 are in the ratio 2:1
Therefore volume of H2 = 24 ml and
Volume of O2 = 12ml
5 days ago
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