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`        a stone of mass 6kg is revolved in a verticle circle of t diameter 6m, such that its speed at a point is minimum at that pointn.if the K.E at the same point is 250J , then minimum P.E a that point is`
9 months ago

## Answers : (1)

veer
18 Points
```							1 mole H2O = 18 mlTherefore , 36 ml H2O = 2 moleNow 1 mole H2O contains 2 mole H and 1mole OTherefore 2 mole H2O has 4 mole H and 2 mole O Oxygen and hydogen both exist as a diatomic molecule. Therefore ,No of moles of H2 = 2And no of moles of O2 is = 1Total volume = 36mlVolume of H2 and O2 are in the ratio 2:1Therefore volume of H2 = 24 ml andVolume of O2 = 12ml
```
5 days ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions