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```
A motorist traveling at 10m/s, was able to bring his car to rest in a distance of 10m. If he had been traveling at 30m/s, in what distance could he bring his cart to rest using the same breaking force?

```
6 years ago

DINESH HIREGANGE
18 Points
```							90m is the answer
```
6 years ago
DINESH HIREGANGE
18 Points
```							v2 = u2 + 2as
0 = 100 + 20a
a = -5m/s2

Again, v2 = u2 + 2as
0 = 900 -10s
-900/-10 = s
s = 90m
```
6 years ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions