Click to Chat
1800-2000-838
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
1. At what temperature the mean speed of the molecules of hydrogen gas equals the escape speed from the earth 2. Estimate the number of collisions per second suffered by a molecule in a sample of hydrogen gas at STP. The mean free path (average distance covered by a molecule between two successive collisions )=1.38×10-5.
1. At what temperature the mean speed of the molecules of hydrogen gas equals the escape speed from the earth
2. Estimate the number of collisions per second suffered by a molecule in a sample of hydrogen gas at STP. The mean free path (average distance covered by a molecule between two successive collisions )=1.38×10-5.
Dear Vinayak Pawar, Solution of Question no 1: Let at temp T K it happens hence the equation is √(8RT/∏M)=√(2GMe/Re) where Re=radious of the earth. Me=mass of the earth. M=molar mass of H2. solving we get T=11810.1 degree =12083.1 K Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best Vinayak Pawar !!! Regards, Askiitians ExpertsSoumyajit Das IIT Kharagpur
Dear Vinayak Pawar,
Solution of Question no 1:
Let at temp T K it happens hence the equation is
√(8RT/∏M)=√(2GMe/Re)
where Re=radious of the earth.
Me=mass of the earth.
M=molar mass of H2.
solving we get T=11810.1 degree
=12083.1 K
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.
All the best Vinayak Pawar !!!
Regards,
Askiitians ExpertsSoumyajit Das IIT Kharagpur
Dear Mr. Vinayak Pawar,Solution of Question no 1:Let at temp T K it happens hence the equation is √(8RT/∏M)=√(2GMe/Re)where Re=radious of the earth; Me=mass of the earth; M=molar mass of H2.solving we get T=11810.1 degree=12083.1 K Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE & AIEEE preparation.All the best. Regards,Askiitians ExpertsPramod KumarIITR Alumni
Dear Mr. Vinayak Pawar,Solution of Question no 1:Let at temp T K it happens hence the equation is
√(8RT/∏M)=√(2GMe/Re)where Re=radious of the earth; Me=mass of the earth; M=molar mass of H2.solving we get T=11810.1 degree=12083.1 K
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE & AIEEE preparation.All the best. Regards,Askiitians ExpertsPramod KumarIITR Alumni
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -