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a person can swim instillwater at 5kmph.he aims on one bank of river at an angle of 300with normal to the flow to reach opposite point of start in 1/√3hr the width of the river is--km
Dear G Somaiah
he reaches at the apposite end of the rever then his horizontal component of speed must be equal to the velocty of the river
vertical componen of velocit =5cos30 = 5√3 /2 km/h
now time teken to cross the river = 1/√3 hr
so 1/√3 = d /5√3 /2
d=5/2 km
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