analysis show that nickel oxide has formulla ni .98 O 1.00 what fraction of the of nickel exist as ni+3 & Ni +2

Let Ni+2 atoms be = x
Let Ni+3 atoms be = 0.98-x
We already know the number of O atoms = 1
Now, by equating total cationic charge = total anionic charge, we will get
(Total Cationic charge) = (Total anionic charge)
2*x + 3*(0.98-x) = 2*1
x = 0.94
% fraction of Ni+2 = (x/0.98)*100 = 95.9 % {putting x = 0.94}
% fraction of Ni+3 = (0.98-x)*100 = 4 % {putting x = 0.94}