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A particle of mass 100 g is thrown verticallyupwards with a speed of 5 m/s. The work done bythe force of gravity during the time the particlegoes up is-
-1.5 is the answer
maximum height reached by the body which is thrown up vertically is h=(U/g)1/2
we know work=F.S
= mg.(u/g)1/2
= 0.1*(50)1/2
=0.5 * (2)1/2
=1.9 N.m
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