A particle of mass 100 g is thrown verticallyupwards with a speed of 5 m/s. The work done bythe force of gravity during the time the particlegoes up is-

-1.5 is the answer

maximum height reached by the body which is thrown up vertically is h=(U/g)^1/2

we know work=F.S

                        = mg.(u/g)^1/2

                       = 0.1*(50)^1/2

                        =0.5 * (2)^1/2

                       =1.9 N.m