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```
find the equation of the circle which passes through the origin and cuts the chords of length 4 and 6 on the +ve side of x-axix and y-axis

```
8 years ago

md salik
31 Points
```							general eqn of circle is x2 + y2 +2gx + 2fy + c =0
since circle passes through origin
for (0,0)
c=0
since circle cuts chord of length 4 unit
for (4,0)
16 + 8g =0
g=-2
for 6 unit on y axis
for (0,6)
36 + 12f =0
f = -3
therefore eqn of circle is x2 + y2 -4x - 6y =0
is the required equation
```
8 years ago
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• 731 Video Lectures
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions