Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Ankit Shukla Grade:


A particle is projected that time its kinetic energy was KE1......and at the top point where vertical velocity is 0 its kinetic energy was KE2 .......

The ratio of KE2 : KE1 is 3:4 ........ find the difference in their velocities ......


Dear ankit

let velocity at the begineeing ii u and angle of projection is θ.

KE1 =1/2 mu2

KE2 =1/2 m(ucosθ)2


KE2 : KE1 is 3:4

so cos2θ  =3/4

θ =30

difference in their velocity =u-ucosθ




sir but answer of this is u/2 ....

8 years ago

Answers : (2)

chaitanya pansare
23 Points

then might be the ques. is asking the difference in vertical velocities which comes out to be usinθ-0 i.e. u/2-0=u/2

8 years ago
Badiuddin askIITians.ismu Expert
147 Points

Dear Ankit Shukla

last answer was on the basis of difference in velocity magnitude.

I think you want difference in velocity vector

Initial velocity =ucosΘ i + usinΘ j

final velocity =ucosΘ i


difference in velocity =ucosΘ i + usinΘ j -ucosΘ i

                             =usinΘ j

                            =u sin30 j

                            =u/2 j

magnitude            =|u/2 j|



Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
Askiitians Experts

8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete AIPMT/AIIMS Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details