A particle is projected ...at that time its kinetic energy was KE1......and at the top point where vertical velocity is 0 its kinetic energy was KE2 ....... The ratio of KE2 : KE1 is 3:4 ........ find the difference in their velocities ...... Dear ankit let velocity at the begineeing ii u and angle of projection is θ. KE1 =1/2 mu 2 KE2 =1/2 m(ucosθ) 2 given KE2 : KE1 is 3:4 so cos 2 θ =3/4 θ =30 difference in their velocity =u-ucosθ =u-u√3/2 =u(1-√3/2) sir but answer of this is u/2 ....

A particle is projected ...at that time its kinetic energy was KE1......and at the top point where vertical velocity is 0 its kinetic energy was KE2 ....... The ratio of KE2 : KE1 is 3:4 ........ find the difference in their velocities ......

Dear ankit let velocity at the begineeing ii u and angle of projection is θ. KE1 =1/2 mu2 KE2 =1/2 m(ucosθ)2 given KE2 : KE1 is 3:4 so cos2θ  =3/4 θ =30 difference in their velocity =u-ucosθ                                      =u-u√3/2                                      =u(1-√3/2)   sir but answer of this is u/2 ....