You should remember the equation of circle in standard form such that:
%7D%7D%5E%7B%7B2%7D%7D%2B%7B%7B%5Cleft(%7By%7D-%7Bk%7D%5Cright)%7D%7D%5E%7B%7B2%7D%7D%3D%7B%7Br%7D%7D%5E%7B%7B2%7D%7D)
The problem provides the coordinates (h,k) of center of circle, hence, you should substitute 3 for h and -1 for k in equation above such that:
%7D%7D%5E%7B%7B2%7D%7D%2B%7B%7B%5Cleft(%7By%7D%2B%7B1%7D%5Cright)%7D%7D%5E%7B%7B2%7D%7D%3D%7B%7Br%7D%7D%5E%7B%7B2%7D%7D)
Notice that the radius is not given but you may find it using the information provided by the problem.
The line that has the equation
and the length of 6 represents a chord of circle.
You may drop a perpendicular from the center of circle to this chord. The perpendicular line drops in the middle of this chord.
You may find the length of perpendicular using the formula:

Notice that ax+by+c represents the equation of chord and
, coordinates of the center.


Notice that the radius of circle represents the hypotenuse of right angle triangle that has the lengths of the legs
and 3.
Using Pythagorean theorem yields:


You may now write the equation of the circle such that:
%7D%7D%5E%7B%7B2%7D%7D%2B%7B%7B%5Cleft(%7By%7D%2B%7B1%7D%5Cright)%7D%7D%5E%7B%7B2%7D%7D%3D%7B38%7D)
Hence, evaluating the equation of circle under given conditions yields %7D%7D%5E%7B%7B2%7D%7D%2B%7B%7B%5Cleft(%7By%7D%2B%7B1%7D%5Cright)%7D%7D%5E%7B%7B2%7D%7D%3D%7B38%7D.)
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%7D%7D%5E%7B%7B2%7D%7D%2B%7B%7B%5Cleft(%7By%7D%2B%7B1%7D%5Cright)%7D%7D%5E%7B%7B2%7D%7D%3D%7B38%7D.)