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A particle is projected ...at that time its kinetic energy was KE1......and at the top point where vertical velocity is 0 its kinetic energy was KE2 .......


The ratio of KE2 : KE1 is 3:4 ........ find the difference in their velocities ......

10 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
							

Dear ankit

let velocity at the begineeing ii u and angle of projection is θ.

KE1 =1/2 mu2

KE2 =1/2 m(ucosθ)2

given

KE2 : KE1 is 3:4

so cos2θ  =3/4

θ =30

difference in their velocity =u-ucosθ

                                     =u-u√3/2

                                     =u(1-√3/2)


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Badiuddin

10 years ago
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