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a line is such that its segment between the straight lines 5x-y-4=0 and 3x+4y-4=0 is bisected at the point (1,5).obtain the equation?
Assume the pts. where they cut as (a,b) and (c,d). Then put them in the equation of the respective lines. Als: a+c=2;b+d=10 Thus you will get 83x-35y+92=0 Thank you
Assume the pts. where they cut as (a,b) and (c,d).
Then put them in the equation of the respective lines.
Als: a+c=2;b+d=10
Thus you will get
83x-35y+92=0
Thank you
wats this a+c=2 and b+d=10........... how??????????
wats this a+c=2 and b+d=10...........
how??????????
Since (1,5) is the mid point of (a,b) and (c,d) therefore (a+c)/2=1 that is why a+c=2 (b+d)/2=5 that is why b+d=10. Thank you
Since (1,5) is the mid point of (a,b) and (c,d)
therefore (a+c)/2=1
that is why a+c=2
(b+d)/2=5
that is why b+d=10.
how do we put these in the eq
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