Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Q.For the quadratic equation 3xsquare + px + 3 + 0 , p>0.If one of the roots is square of the other,then p=a) 1/3 b) 1 c) 3 d) none of these
let roots be q,q2, product of roots= 3/3 =1, q3=1, q=1, sum of roots= -p/3
sir i also tried the same thingby that p is coming out to be -6but the answer given is option (c)
since eqn says one root is square of other so if one root is q then other root is q square therfore qcube from product of roots is1 therefore q=1 or q=w(omega)complex root q=1 is rejected as p =-6 which is not possible therfore q=w and 1+w+wsquare=0 which is property of complex no since w is root there 3wsquare +pw +3=0 there p=3
thank you sir
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !