How ll v calculate disKa,HCOOH =1.8 x 10^-4,Ka,CH3COOH=1.8 x 10^-5,Kb,NH3=1.8 X 10^-5,Ka1,H2S= 10^-7,Ka2,H2S=10^-14LOG 1.8 =.26COLUMN 1COLUMN 2A)10^-5 M HClP) alpha H2Osol > .1 M H2S sol(degree ofdissociation)B)CH3COOH sol (pH 4.74)Q)[OH-]= NH4OH sol (pH 9.26)C) .1 M CH3COOH sol =R)alpha1 M HCOOH sol(degree ofdissociationof weakelectrolytic)D).1 M weak acid HA1(Ka=10^-5)S)pH<.01 M weak acid HA2 (Ka= 10^-6)
RIYA GUPTA , 12 Years ago
Grade 12
