given a hexagon of sides AB,BC,CD,DE,EF,FA with centre at O

then prove that AB+AC+AD+AE+AF=6AO

Question

given a hexagon of sides AB,BC,CD,DE,EF,FA with centre at O then prove that AB+AC+AD+AE+AF=6AO

Ramesh V · Answer

If R be the resultant, then R=AB+AC+AD+AE+AF =AB+(AD+DC)+AD+(AD+DE)+AF Now AF and DC are two equal vectors in opposite directions and hence they cancel each other. Similarly AB and DE cancel each other. so R = 3A =6AO where is the mid. point of AD i. e. the centroid of the hexagon.

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given a hexagon of sides AB,BC,CD,DE,EF,FA with centre at O then prove that AB+AC+AD+AE+AF=6AO

given a hexagon of sides AB,BC,CD,DE,EF,FA with centre at O

then prove that AB+AC+AD+AE+AF=6AO

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