pl ans my question on simple coordination compounds please please 4hrs ago posted

r u sure that the book is correct

it shld be +3 instead of +2 in [Fe(NH3)6]^+2

acc to me the one with oxidation number 2 will have co ordination number 4

and the one with 3 oxidaton number will have co ordination number 6

so fe with oxidation number 2 will not exhibit [Fe(NH3)6]^+2 as the co ordination number here is 6

so the possibile formula is [Fe(NH3)4]^+2 OR [Fe(NH3)6]^+3

so if u are taking [Fe(NH3)6]^+3 ------- config is -------- 3d6 , 4s2

now remove 3 e

then u will get ------------ 3d5 -------- will not pair up --------------- so u will get sp3d2 ---- dezired answer

is what i think

they must by mistake printed +2 instead of +3

with [Fe(NH3)6]^+3

also when u r filling using CFT t2g^5 eg^0

the u will get an unpaired electron in t2g part of d orbitals

and on filling NH3 u will get d2sp3 ---------> inner orbital complexes

but it is also a paramagnetic complex with 1 unpaired electron so it shld be an outer orbital complex -------------> sp3d2

is what i think

sir both CN minus and NH3 are strong field ligands.

in many books it is given [Fe(CN-)6]^3- as d2sp3. i understood this.

so in [Fe(NH3)6]^3+ how can it be sp3d2. WHEN BOTH COMPOUNDS ARE d5 configuration with Fe3+ ??

i mean TO KNOW WHY IT WILL NOT PAIR UP??? and give d2sp3 ???
just tell me this sir please...