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Grade: 12
        

1180_15271_3chemnest10.jpg

8 years ago

Answers : (1)

vikas askiitian expert
509 Points
							

ans4.4=>

I = integral 5/(x2+4)(x2+9) = integral k

let  x2 = t then

k = 5/(t+4)(t+9)

using partial fractions we get

k = 1/t+4 - 1/t+9

now integral becomes

I = 1/t+4 - 1/t+9 = [1/x2+4 - 1/x2+9]dx limit from 0 to infinity

I = 1/2 tan-1x/2 - 1/3 tan-1x/3               lim 0 to infinity

I = 1/2 * pi/2 - 1/3 * pi/2 = pi/12

 

option b) is correct

8 years ago
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