 Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        If the line y=√3X+k touches the circle Xsquare+Ysquare=16, then k=??????`
8 years ago

```							x2 + y2 = 16
radius of this circle = a = 4
line is touches the circle if C = a(1+m2)1/2 ............1
C is y intercept , a is radius of circle , m is slope of line
m = 31/2 , a = 4 , C = k
putting all these values in eq 1
k = 4(1+3)1/2 = 4*2 = 8
```
8 years ago
```							if the line touchs the circle then distance of centre of circle from the line must be the radius of circle.
and the centre of circle is (0,0).
hence distance of the line y=root 3 x +k from (0,0) is 4 units
hence-
( 0-root3 X 0-k)/root[3+1]  =4
by formula of distance of a point from a line.
on solving it we get k =8
if u like my answer then approve it.
```
8 years ago
```							thnx.....
```
8 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Discuss with colleagues and IITians

View all Questions »  ### Course Features

• 728 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions