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Grade: 12

                        

What is the reduction potential of the following half cell under the specified conditions and at 298 K? (i) Cl2 + 2e ---> 2Cl- (negative ion), [Cl-] = 0.10M, partial pressure of Cl2 = 0.10 atm. I need to know how do we substitute the partial pressure of cl2, I was said that first we have to convert it into concentration and then substitute in nernst equation, but i dont know the exact answer. Could anyone help me out with this please?

9 years ago

Answers : (1)

SAGAR SINGH - IIT DELHI
879 Points
							

Dear student,

Use pressure to calculate concentration-

c=P/RT

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Askiitians Expert

Sagar Singh

B.Tech, IIT Delhi

9 years ago
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