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```
Integral 1+tan(x)tan(x+a)
Integral  1+tan(x)tan(x+a)

```
10 years ago

509 Points
```							I = [1 + tanxtanx+a]dx
I = [1 + (sinx/cosx)(sinx+a/cosx+a)]
I = [cosx+acosx+sinx+asinx]dx/cosxcosx+a                  (using , cosacosb+sinasinb = cosa-b)
I = (cosa)dx/cosxcosx+a
multiply divide by sina
I = cota (sina)dx/cosxcosx+a          ...............1
sina = sin[(x+a)-x] = sin(x+a)cosx - cos(x+a)sinx        ............2
putting 2 in eq 1
I = cota [ tan(x+a) - tanx]dx
I = cota [ logsec(x+a) - logsecx] + c
I = cota { log[sec(x+a)/secx] } + c
this is the required integral
approve my ans if u like it
```
10 years ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions