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I already know how to get the section formula with the help of similarity of triangles concept, what i want to know know is whether i can get the same formula using the concept of distance between two coordinate points, i.e. for A(x1,y1) and B(x2,y2) distance AB = now suppose that a point C divides AB in the ratio m : n, then using the distance formula and using can we get coordinates of C as .

I already know how to get the section formula with the help of similarity of triangles

concept, what i want to know know is whether i can get the same formula using the concept of distance between two coordinate points,

i.e. for A(x1,y1) and  B(x2,y2) distance AB =

now suppose that a point C divides AB in the ratio m : n, then using the distance formula

and using

can we get coordinates of C as

.


10 years ago

419 Points
							Dear Neel
You have to also apply the slope of AC= slope of CB
it will give you y-y1/x-x1 = y-y2/x-x2
as you are using only distance relation that is not sufficient.line ac and cb can be inclined also and can
satisfy ac/cb=m/n

All the best.
AKASH GOYAL

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10 years ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions