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`        the curve y=x3+x2-x has two horizontal tangents ..the distance b/w these two tangents is `
7 years ago

419 Points
```										Dear Anshu
For horizontal tangents put y'=0 from which one can get
x=1/3 and -1 get the corresponding y value which are-5/27 and 1
So the distance between horizontal tangents is 5/27+1=32/27
All the best.
AKASH GOYAL

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```
7 years ago
510 Points
```										y=x^3 + x^2 -x
dy/dx =3x^2 + 2x -1
slope of horizontal tangent(dy/dx) = 0
3x^2 + 2x -1=0
x=-1,1/3
y=1,-5/27
tangents are y=1 and y=-5/27
distance  bw tangents=32/27
```
7 years ago
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