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if (-2,1) and (3,2) are the vertices of a parallelogram , the equation of diagonal is x+y+1=0 and the length of a side is 6 units . Find the other two vertices of the parallelogram .
since the distance b/w the two given vertices is not 6. this implies that the other side let(x,y) will be 6
thus we can get two conditions
(x+2)2 + (y-1)2 = 36
& x+y+1=0
thus by solving these two equations we can get one of the vertices
then the remaining vertices can be evaluated by distance formula or any other method
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