AJIT AskiitiansExpert-IITD
Last Activity: 14 Years ago
Dear Chanchal ,
is the formulae for the incentre of triangle and the centroid of a triangle is given by (x2 , y2) = (x1+x2+x3/3 .y1+y2+y3/3)
so , G = (-36+20+0/3 , 7+7+(-8)/3) ; G = (-16/3 , 2)
a = BC = 25 , b =AC = 39 , c =AB = 56
therefore ,
I = [25*(-36)+39*(20)+56*(0)/(25+39+56), 25*(7)+39*(7)+56*(-8)/(25+39+56) ]
I =[-1 , 0]
therfore ,
IG = 4.77 (use simply heroes formulae)
GOOD LUCK !!!
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