Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
The point A divides the join of P(-5,1) and Q(3,5) in the ratio K:1. Find the two values of k for which the area of triangle ABC, where B is (1,5) and C is (7,-2), is equal to 2 units.
Dear chanchal ,
let the co-ordinates of A be (x ,y). then x = 3k-5/k+1 , y =5k+1/k+1
now use the determinant formulae for calculating the area of triangle ,
we get ,
|14k-66/k+1| = 4
taking +4 and -4 separately ,
14k-66 =4k+4 gives k =7 and 14k-66 = -4k-4 gives , k= 31/9
Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation. Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
Win exciting gifts by answering the questions on Discussion Forum.
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !