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A uniform chain of length 2L is hanging in equilibrium position, if end B is given a slightly downward displacementthe imbalance causes an acceleration. Here pulley is small and smooth & string is inextensibleThe velocity v of the string when it slips out of the pulley (height of pulley from floor > 2L)(A) √(gL/2)(B) √(2gL)(C) √(gL) (D) none of these

Navneet Kumar , 6 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 6 Years ago

 
\lambda(L+x)g-T=\lambda(L+x)a
T-\lambda(L-x)g=\lambda(L-x)a
Where lambda is mass per unit length of both ends 
Solve these equations by adding them give you
2xg=2La
(x/L)g=a
And  these question is specially check you concept in NLM
 
Regards
Arun

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