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Grade: 10
        
x, y and z are unequal positive numbers. Which of the following relations is possible?
 
(A) cosθ = (x²+y²+z²)/(xy+yz+zx)
(B) secθ = (x²+y²+z²)/(xy+yz+zx)
(C) sinθ = (x²+y²+z²)/(xy+yz+zx)
(D) cosecθ = (xy+yz+zx)/(x²+y²+z²). 
2 months ago

Answers : (1)

Vikas TU
9096 Points
							
Dear student 
x, y , z is any positive numbers 
We know that 
Cos Q and SinQ can not be greater than 1 
So, A nd C can not be the option because in that case numerator is greater than denominator. 
Sec Q = 1/CosQ 
which is greater than 1 
again Cosec Q can not be less than 1 
So, B is the correct ans 
Hope this helps 
Goos Luck  
2 months ago
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