x, y and z are unequal positive numbers. Which of the following relations is possible? (A) cosθ = (x²+y²+z²)/(xy+yz+zx) (B) secθ = (x²+y²+z²)/(xy+yz+zx) (C) sinθ = (x²+y²+z²)/(xy+yz+zx) (D) cosecθ = (xy+yz+zx)/(x²+y²+z²).

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Vikas TU · Answer

Dear student x, y , z is any positive numbers We know that Cos Q and SinQ can not be greater than 1 So, A nd C can not be the option because in that case numerator is greater than denominator. Sec Q = 1/CosQ which is greater than 1 again Cosec Q can not be less than 1 So, B is the correct ans Hope this helps Goos Luck

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x, y and z are unequal positive numbers. Which of the following relations is possible? (A) cosθ = (x²+y²+z²)/(xy+yz+zx) (B) secθ = (x²+y²+z²)/(xy+yz+zx) (C) sinθ = (x²+y²+z²)/(xy+yz+zx) (D) cosecθ = (xy+yz+zx)/(x²+y²+z²).

x, y and z are unequal positive numbers. Which of the following relations is possible?

(A) cosθ = (x²+y²+z²)/(xy+yz+zx)
(B) secθ = (x²+y²+z²)/(xy+yz+zx)
(C) sinθ = (x²+y²+z²)/(xy+yz+zx)
(D) cosecθ = (xy+yz+zx)/(x²+y²+z²).

1 Answers

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x, y and z are unequal positive numbers. Which of the following relations is possible? (A) cosθ = (x²+y²+z²)/(xy+yz+zx) (B) secθ = (x²+y²+z²)/(xy+yz+zx) (C) sinθ = (x²+y²+z²)/(xy+yz+zx) (D) cosecθ = (xy+yz+zx)/(x²+y²+z²).

x, y and z are unequal positive numbers. Which of the following relations is possible? (A) cosθ = (x²+y²+z²)/(xy+yz+zx)(B) secθ = (x²+y²+z²)/(xy+yz+zx)(C) sinθ = (x²+y²+z²)/(xy+yz+zx)(D) cosecθ = (xy+yz+zx)/(x²+y²+z²).

1 Answers

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x, y and z are unequal positive numbers. Which of the following relations is possible?

(A) cosθ = (x²+y²+z²)/(xy+yz+zx)
(B) secθ = (x²+y²+z²)/(xy+yz+zx)
(C) sinθ = (x²+y²+z²)/(xy+yz+zx)
(D) cosecθ = (xy+yz+zx)/(x²+y²+z²).