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`        x, y and z are unequal positive numbers. Which of the following relations is possible? (A) cosθ = (x²+y²+z²)/(xy+yz+zx)(B) secθ = (x²+y²+z²)/(xy+yz+zx)(C) sinθ = (x²+y²+z²)/(xy+yz+zx)(D) cosecθ = (xy+yz+zx)/(x²+y²+z²). `
8 months ago

Vikas TU
11138 Points
```							Dear student x, y , z is any positive numbers We know that Cos Q and SinQ can not be greater than 1 So, A nd C can not be the option because in that case numerator is greater than denominator. Sec Q = 1/CosQ which is greater than 1 again Cosec Q can not be less than 1 So, B is the correct ans Hope this helps Goos Luck
```
8 months ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions