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U.V. light of wavelength 800 Å & 700 Å falls on hydrogen atoms in their ground state & liberates electrons with kinetic energy 1.8 eV and 4 eV respectively. Calculate planck’s constant.

U.V. light of wavelength 800 Å & 700 Å falls on hydrogen atoms in their ground state & liberates
electrons with kinetic energy 1.8 eV and 4 eV respectively. Calculate planck’s constant.

Grade:11

1 Answers

VAISHNAVI BATHINA
130 Points
8 years ago
Energy difference =hc/wavelength 
here h=plancks constant

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