two spherical conductors B &C having equal radii and carrying equal charges with them repel eachother with a force F when kept at a small distance apart . a third spherical conductor A having same charge as that of B but uncharged is brought in contact with B and then with C and finally removed away from both . what is the new force of repulsion between B & C ?

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Arun · Answer

Let B and C have charge Q each initially and are seperated by r distance. ∴ Coulomb force between them, F= r 2 KQ 2 ​ ...........(1) Now an identical uncharged spherical conductor A is brought in contact with B. They will share equal charge among themselves. Charge on A= 2 Q ​ Charge on B= 2 Q ​ Now the conductor A is brought in contact with C. They will share equal charge among themselves. ∴ Charge on A or C = 2 Q+ 2 Q ​ ​ = 4 3Q ​ New coulomb force between B and C: F ′ = r 2 K 2 Q ​ × 4 3Q ​ ​ = 8 3 ​ r 2 KQ 2 ​

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