Grade 11Discuss with Askiitians Tutors
trignometry
1) solve sinx sin3x=1/2
1 Answer
Rinkoo Gupta
sinx(3sinx-4sin^3x)=1/2
2sin^2x(3-4sin^2x)=1
let sinx=t
2t^2(3-4t^2)=1
6t^2-8t^4-1=0
8t^4-6t^2+1=0
put t^2=y, we get
8y^2-6y+1=0
(2y-1)(4y-1)=0
y=1/2, 1/4
t^2=1/2, 1/4
t=1/root2, 1/2
=> sinx=1/root2 , 1/2
=> x=pi/4, pi/6
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
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