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trignometry 1) solve sinx sin3x=1/2
sinx(3sinx-4sin^3x)=1/22sin^2x(3-4sin^2x)=1let sinx=t2t^2(3-4t^2)=16t^2-8t^4-1=08t^4-6t^2+1=0put t^2=y, we get8y^2-6y+1=0(2y-1)(4y-1)=0y=1/2, 1/4t^2=1/2, 1/4t=1/root2, 1/2=> sinx=1/root2 , 1/2=> x=pi/4, pi/6Thanks & RegardsRinkoo GuptaAskIITians Faculty
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