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Grade: 12th pass
        
To a man walking at the rate of 2km/hr, rain appears to fall vertically.When he doubles his speed,it appears to fall at 300 to the vertical.Find the actual velocity of the rain.
2 years ago

Answers : (2)

Eshan
askIITians Faculty
2095 Points
							Let the drop fall at angle\thetaand speedv. Let the speed o man beu. Since the rain appears to fall vertically,u=vsin\theta

When the man doubles the speed, the relative speed of rain backwards=2u-vsin\theta
The relative speed of rain vertically downward=vcos\theta

Since it forms angle30^{\circ}with vertical. Hencetan30^{\circ}=\dfrac{2u-vsin\theta}{vcos\theta}

Solving the two gives the value of v.
2 years ago
Eshan
askIITians Faculty
2095 Points
							The answer comes out to bev=4km/hrand\theta=30^{\circ}
						
2 years ago
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