Guest

Solve please.

Solve please.

Question Image
Grade:12

1 Answers

Ravi
askIITians Faculty 69 Points
7 years ago
•31/2x31/4x31/8x31/16x…...........upto infinty
•31/2 +1/4+1/8+1/16 +1/32 …...........
•Now, 1/2 +1/4+1/8+1/16 +1/32+... is an infinite series with
common ratior= (1/4)/(1/2)= (1/2)

•So, the sum of an infinite GP with r<1 is S(inf.)= a/(1-r)

•Hence, Series S:31/2 +1/4+1/8+1/16 +1/32 ….......... = 3[(1/2)/(1-r)]
•S= 3[(1/2)/(1-(1/2))]
•S= 3[1]
•S=3

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free