MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade:
        
 
Sir I'm confused between (R) wave function,probability wave function(4*3.14r^2R^2) and probability density(R^2)  graphs shown in op tandon.
I'm not understanding what is representing what?
he is also mentioning e density is maximum at nucleus for 1s orbital????I request u to provide a detailed explanation if possible of the graphs and also about e density variation.
4 years ago

Answers : (1)

shubham khanna
46 Points
							
PLEASE ACCEPT POST IF U LIKE MY ANSWER........
Acc. to the schodinger wave eqn. the probability of finding an e- in an atom is given by the -
probability wave function(4*3.14r^2R^2). By observing graph for 1s you will see that the function dec. linearly with inc. in r, which means the probaility of finding e- or electron density is more near nucleus.
 
4 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 728 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details