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sir how to solve it image attached

sir how to solve it
image attached

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1 Answers

viswanath
40 Points
6 years ago
Take tan7=a.
  tan7tan53tan67=a{(√3-a)/(1+√3a)}{( √3+a)/(1-√3a)}         since tan60 =√3
 =a(3-a2)/(1-3a2)  = (3a-a3)/(1-3a2) =(3tan7-tan37)/(1-3tan27)=tan (3×7)=tan 21
 tan21 tan69=1.             

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