Simple perobability question In a two child family, one child is boy.what is the probability that the other child is girl? my ans is 2/3 but the given answer is ¾ plaese show the whole process

Let B---> Event that child is a boy

      G---> Event that child is a girl

In two child family, the sample space is:

{BB, BG, GB, GG}

BG and GB are listed separately because BG represents a family in which the oldest child is a boy, while GB represents a family in which the oldest child is a girl. Each of the above combinations is equally likely. Since we're told that one child (we don't know which) is a boy, we can eliminate the GG combination. Thus, our remaining possible combinations are:

S={BB, GB, BG}

Where S is the new sample space(total no. Of outcomes)

F={GB,BG}

Where F is the set of favourable outcomes.

Reqd probability= n(F)/n(S)

                          = 2/3

According to me, your answer is correct(there may be some misprint in the material provided to you).

If they could have asked the probability that atleast one child is a girl of there are two children in a family,then your answer could have been 3/4.