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`        Plzz..ans.  this question..[calculate the pH of a mixture containing 50 mililitre  of 1(N) HCl and 30 mililitre of 1(N) NaOH].((Ans. ....0.6)).`
one year ago

```							Mole = concentration x volumemole of NaOH = 30ml x 1 = 30.0mole of HCl = 50ml x 1= 50.030 mole of NaOH exactly neutralized by 30 mole of HCl.NaOH + HCl = NaCl + H2Othat is 50 -30 = 20 HCl moleCon of H+ = no of mole of H+ / total volume of solution (50+ 30 ml = 80 ml)= 20/80 = 0.25pH = - log ( H+)= - log (1/4) = 0.6021s0 the pH of solution will be 0.6021
```
one year ago
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