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Mole = concentration x volume
mole of NaOH = 30ml x 1 = 30.0
mole of HCl = 50ml x 1= 50.0
30 mole of NaOH exactly neutralized by 30 mole of HCl.
NaOH + HCl = NaCl + H2O
that is 50 -30 = 20 HCl mole
Con of H+ = no of mole of H+ / total volume of solution (50+ 30 ml = 80 ml)
= 20/80 = 0.25
pH = - log ( H+)
= - log (1/4) = 0.6021
s0 the pH of solution will be 0.6021
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