Last Activity: 5 Years ago
Dear studentPlease see there are two points with the samename P2consider upper point P1 and using KCL(5 – Vp1)/ 2 = ( Vp1 / 10 ) + ((Vp1 – 5)/2 )Vp1 = 50 /11Ip1 to p2 = 5/11Therefore current is 0.45 ampere
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Last Activity: 2 Year ago(s)