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please solve this............ please.............................................

DIBYA RASHMI NAIK , 5 Years ago
Grade
anser 1 Answers
Saurabh Koranglekar

Last Activity: 5 Years ago

Dear student

Please see there are two points with the samename P2

consider upper point P1 and using KCL

(5 – Vp1)/ 2 = ( Vp1 / 10 ) + ((Vp1 – 5)/2 )

Vp1 = 50 /11

Ip1 to p2 = 5/11

Therefore current is 0.45 ampere

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