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please solve this............ please.............................................
please solve this............ please.............................................
1 Answer
Saurabh Koranglekar
Dear student
Please see there are two points with the samename P2
consider upper point P1 and using KCL
(5 – Vp1)/ 2 = ( Vp1 / 10 ) + ((Vp1 – 5)/2 )
Vp1 = 50 /11
Ip1 to p2 = 5/11
Therefore current is 0.45 ampere
Please see there are two points with the samename P2
consider upper point P1 and using KCL
(5 – Vp1)/ 2 = ( Vp1 / 10 ) + ((Vp1 – 5)/2 )
Vp1 = 50 /11
Ip1 to p2 = 5/11
Therefore current is 0.45 ampere
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