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`        Please solve above 2 problems with deatailed solution kindly .thankyou`
8 months ago

1236 Points
```							1. ​we know that trianagle inequality states that    |z1+z2+z3| less than equal to |z1|+ |z2|+ |z3|    now,  |z1-1+1| less than equal to |z1-1|+|1| = 2    similarly |z2-2+2| less than equal to |z2-2|+|2| = 4    and |z3-3+3| less than equal to |z3-3|+|3| = 6   adding all these inequalities, we obtain  |z1+z2+z3| less than equal to 2+4+6=12   hence the greatest value of  |z1+z2+z3| is 12, which occurs when z1=2, z2=4 and z3=62. we can write z= (1+cos2pi/5) – isin(2pi/5)    so let argz= x    then tanx= – sin(2pi/5)/(1+cos2pi/5) = – tanpi/5    so, argz = – pi/5
```
8 months ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions