Please give the solution.

The circle R lies inside the circle S as shown in the fig. Hence,
Ar(circle R) = pi x r_R²= 4 sq. inches
So,
r_R= 2/(pi)<sup>1/2

Accordingly,</sup>
r_S=2r_R= 4/(pi)½

And area(circle S)= pi x r_S²= pi x [4/(pi)^1/2]²
= pi x 16/pi
= 16 sq. inches