+91-705-589-3577
FlagBACK
Flag Discuss with Askiitians Tutors> Please give me solution of this question ...
question mark

Please give me solution of this question plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

Suraj Kumar , 6 Years ago
Grade
anser 1 Answers
Aditya Gupta
hello suraj, notice that u can write the given expression as
(a1*x + a2)^2 + (a2*x + a3)^2 + …....... + (a(n-1)*x + an)^2 is less than or equal to 0
since these are all square terms and hence positive (greater than or equal to 0), so this expression will have to be exactly 0.
or (a1*x + a2)^2 + (a2*x + a3)^2 + …....... + (a(n-1)*x + an)^2= 0
which is possible iff
a1*x + a2= 0, a2*x + a3= 0, …......., a(n-1)*x + an= 0
or, – x= a2/a1= a3/a2= …........= an/a(n-1)
which is obviously a GP (geometric progression) with common ratio of negative x.
kindly approve :)
Last Activity: 6 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Other Related Questions on discuss with askiitians tutors

question mark
Please send the full solution as soon as possible 🙏 
discuss with askiitians tutors
1 Answer Available

Last Activity: 3 Years ago

question mark
I got 80% in jee mains and am from sc category . Will i get a good NIT
discuss with askiitians tutors
1 Answer Available

Last Activity: 3 Years ago

question mark
Looking for an integrated JEE+NEET Coaching Classess for 2 years along with an ongoing normal syllabus related classes followed by regular revision tests, please.
Thanks
Gopinath [F/O Class 10th Student-Qatar]
discuss with askiitians tutors
1 Answer Available

Last Activity: 4 Years ago

question mark
Ntse coaching for class 9 ncert student, fee and schedule
discuss with askiitians tutors
1 Answer Available

Last Activity: 4 Years ago

question mark
Can a class 9 student take admission in the course, 2- what is the duration and mode of full course ie how many student in one class. 
discuss with askiitians tutors
1 Answer Available

Last Activity: 4 Years ago