N=2³×3²×5⁴×7¹ then find no of divisors of the form 4 (lambda)+2 .(lambda~N)

Question

N=2³×3²×5⁴×7¹ then find no of divisors of the form 4 ​ (lambda)+2 .(lambda~N)

Arun · Answer

Dear student factors of 4lambda + 2 form = 2 * 3 * 5 * 2 = 60 Hope it helps In case of any difficulty, please feel free to ask again Thanks and regards

Vikas TU · Answer

Dear student Question is not clear Please upload an image. We will happy to help you. Good luck Cheers

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N=2³×3²×5⁴×7¹ then find no of divisors of the form 4 (lambda)+2 .(lambda~N)

N=2³×3²×5⁴×7¹ then find no of divisors of the form 4 (lambda)+2 .(lambda~N)

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N=2³×3²×5⁴×7¹ then find no of divisors of the form 4 ​ (lambda)+2 .(lambda~N)

N=2³×3²×5⁴×7¹ then find no of divisors of the form 4​ (lambda)+2 .(lambda~N)

2 Answers

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N=2³×3²×5⁴×7¹ then find no of divisors of the form 4 (lambda)+2 .(lambda~N)

N=2³×3²×5⁴×7¹ then find no of divisors of the form 4 (lambda)+2 .(lambda~N)