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Grade: 12th pass
        
Let a and b be the roots of the equation x² - px + q = 0. Define the sequence x= a + b. Then xn+1 is given by
 
a)px- qxn-1
b)pxn + qxn-1
c)qxn - pxn-1
d)qxn + pxn-1
4 months ago

Answers : (1)

Rajat
137 Points
							
Xn+1=a^(n+1) + b^(n+1)
= (a^n+b^n)(a+b) - ab[a^(n-1)+b^(n-1)]
= Xn(p)-X(n-1)q
 Option A is correct
All the best
3 months ago
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