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`        Let a and b be the roots of the equation x² - px + q = 0. Define the sequence xn = an  + bn . Then xn+1 is given by a)pxn - qxn-1b)pxn + qxn-1c)qxn - pxn-1d)qxn + pxn-1`
7 months ago

Rajat
176 Points
```							Xn+1=a^(n+1) + b^(n+1)= (a^n+b^n)(a+b) - ab[a^(n-1)+b^(n-1)]= Xn(p)-X(n-1)q Option A is correctAll the best
```
6 months ago
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