in an X-ray apparatus an electron is accelerated by a stop through a 10kV potential difference Calculates the maximum force that a magnetic field of 0.957T can exert on this electron.
Shrenik , 7 Years ago
Grade 12
1 Answers
Arun
Last Activity: 4 Years ago
If electrons are accelerated to a velocity v by a potential difference V and then allowed to collide with a metal target, the maximum frequency of the X-rays emitted is given by the equation:
mv
2
=eV=hν
or, λ
min
=
10
3
1240
∗10
−9
=124nm=12.4A
∘
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free
Enter text here...
Other Related Questions on discuss with askiitians tutors