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`        If a mass M is split into two parts of m and M-m amd placed at separation r then find the maximum force of attraction between two parts`
2 years ago

Arun
23742 Points
```							Dear student F = G m (M -m)/r^2 maximize m(M-m) where M is a constant total massy = m(M-m) = M m - m^2 dy/dm = M - 2 m that = 0 when M = 2 m m = M/2 so split it in two.Hence find the force that will be maximum. RegardsArun (askIITiams forum expert)
```
2 years ago
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions