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http://www.askiitians.com/forums/IIT-JEE-Entrance-Exam/2-5-8-100-terms-3-5-7-100-terms_104026.htm

http://www.askiitians.com/forums/IIT-JEE-Entrance-Exam/2-5-8-100-terms-3-5-7-100-terms_104026.htm

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1 Answers

SHAIK AASIF AHAMED
askIITians Faculty 74 Points
7 years ago
Hello student,
for 2,5,8,............100 terms
for 3,5,7.............100 terms
as we can see that second series hasall odd termstill 3+(99)2=201
and 1stseries has last term as 2+(99)3=299
as we can see from aboveevery alternate termof 1stseries is present in 2ndalso.(as they are odd)
So the sum ofcommon terms of Ap’s=5+11+17+.......+201
=n/2(a+l)
=34/2(5+201)
=17(206)
=3502
Thanks and regards
Shaik Aasif
askIITians faculty

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