MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
howt to solve problem no. 32
Q:The refractive index for the material of a 60 prism is1.5.then the angle of incidence for minimum deviation is nearly?
one year ago

Answers : (1)

Suraj Singh
148 Points
							Hey kashif U can first find minimum deviation of a prism by using formula ü=[sin{(A+d) /2}]/sin (A/2)..  Where d is the minimum deviation and u is its refractive index...  Then U can use the concept that at min deviation angle of incidence is equal to angle of emergence..  So use the formula d=i+e-A...  Since i=e..  Then u can find i...  Hope U like it...
						
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 3,180 off

COUPON CODE: SELF20


Course Features

  • 728 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 3,180 off

COUPON CODE: SELF20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details