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# Hi,I have a sum on Permutation & Combination. Its as follows. What is the total number of ways in which Robert can distribute 9 distinct chocolates among 8 people such that each one gets atleast one chocolate?

Harsh Patodia IIT Roorkee
7 years ago
Hi

First u need to select 8 chocolates out of nine and distribute one to each
(Since each has to get atleast 1)
This can be done in 9C8 x 8! ways

Now the remaing 1 chocolate can be given to any one student i.e 8choices
So total ways will be 9x9C8x8! ways.

Meeta
8 Points
7 years ago
Hi,
Thanks for the reply. But the answer given is different, it says 36 * 8! is the correct answer. Please let me know how to get to that. Thanks