Hi,

I have a sum on Permutation & Combination. Its as follows. What is the total number of ways in which Robert can distribute 9 distinct chocolates among 8 people such that each one gets atleast one chocolate?

Hi

First u need to select 8 chocolates out of nine and distribute one to each
(Since each has to get atleast 1)
This can be done in ⁹C₈ x 8! ways

Now the remaing 1 chocolate can be given to any one student i.e 8choices
So total ways will be 9x⁹C₈x8! ways.