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`        Hello sir /madam please solve the above property i am not understaning .kindly please solve the question thankyou.`
one year ago

1714 Points
```							|z1 – z2|=|z1 + z2|divide by |z2| on both sides|z1/z2–1|=|z1/z2+1|let z1/z2=zso |z-1|=|z+1|but |z-1| and |z+1| represent the distance of z from 1 and -1 respectively. for both these distances to be equal, z must lie on the perpendicular bisector of the line joining 1 and –1, which happens to be the imaginary axis. hence z lies on the imaginary axis and hence z=z1/z2 is purely imaginary.this means that argz=+-pi/2arg(z1/z2)=+-pi/2or arg(z1) – arg(z2)=+-pi/2
```
one year ago
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• 731 Video Lectures
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions