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The accelaration of man with respect to ground is
g=a+a0
hence
a=g-a0
From force diagram of man
T-mg=ma
T-mg=m(g-a0)
T-mg=mg-ma0
T+ma0=2mg................1
From force diagram of block A
T-m/2*g=m/2*a0.
T+m/2*a0=m/2*g...............2
subtracting equation 2 and 1
T+m/2*a0-(T+ma0)=m/2g-2mg
m/2a0-ma0=-3mg/2
-ma0/2=-3mg/2
ma0/2=3mg/2
a0=3g
From Equation 2
T+m/2*a0=m/2*g
T=m/2g-m/2a0
T=m/2g-m/2*3g
T=-2gm
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