an object of mass 2 kg is thrown upward with an initial velocity of 4m/s.it is acted upon by constant gravitational force and mysterious force of 2N which always opposes the motion of the object.what is the position of the object at t=0.5s ?

Question

Radha Shukla · Answer

3.125m above ground you can apply second equation of motion since force opposes acceleration so net acceleration will be 9.. by using this data apply 2nd equation

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an object of mass 2 kg is thrown upward with an initial velocity of 4m/s.it is acted upon by constant gravitational force and mysterious force of 2N which always opposes the motion of the object.what is the position of the object at t=0.5s ?

an object of mass 2 kg is thrown upward with an initial velocity of 4m/s.it is acted upon by constant gravitational force and mysterious force of 2N which always opposes the motion of the object.what is the position of the object at t=0.5s ?

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an object of mass 2 kg is thrown upward with an initial velocity of 4m/s.it is acted upon by constant gravitational force and mysterious force of 2N which always opposes the motion of the object.what is the position of the object at t=0.5s ?

an object of mass 2 kg is thrown upward with an initial velocity of 4m/s.it is acted upon by constant gravitational force and mysterious force of 2N which always opposes the motion of the object.what is the position of the object at t=0.5s ?

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